[x+(y+1)][x-(y+1)]
=x²-(y+1)²
=x²-y²-2y-1(a+b+c)(a-b-c)也是一样(a+b+c)(a-b-c)=[a+(b+c)][a-(b+c)]=a²-(b+c)²=a²-b²-c²-2bc
[x+(y+1)][x-(y+1)]求平方差公式计算过程
[x+(y+1)][x-(y+1)]求平方差公式计算过程
数学人气：171 ℃时间：2020-01-29 06:32:06
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