x2+y2-4x+6y+13=(x-2)2+(y+3)2=0,
可得x-2=0,y+3=0,
则x=2;y=-3.
已知x2+y2-4x+6y+13=0,求x和y的值分别是多少?
已知x2+y2-4x+6y+13=0,求x和y的值分别是多少?
数学人气:814 ℃时间:2019-11-09 12:38:33
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