f(x+1)是偶函数
f(0)=f(2)
f(x)在区间【1,正无穷】是单调递减
f(1)>f(0)
设函数f(x)在区间【1,正无穷】是单调递减,f(x+1)是偶函数,判断f(1)与f(0)的大小
设函数f(x)在区间【1,正无穷】是单调递减,f(x+1)是偶函数,判断f(1)与f(0)的大小
数学人气:972 ℃时间:2019-10-23 07:28:12
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