将下列函数化为y=a(x+m)^2+k形式并指出顶点坐标和对称轴 y=x^2-2x+4 y=x(8-x) y=100-5t^2 y=(t-2)(2t+1)

y=x^2-2x+4=x^2 -2x+1+3=(x-1)^2 +3对称轴x=1,顶点坐标(1,3)y=x(8-x)=-x^2 +8x=-(x^2 -8x+16-16)=-(x-4)^2 +16对称轴x=4,顶点坐标(4,16)y=100-5t^2=-5t^2 +100对称轴x=0,顶点坐标(0,100)y=(t-2)(2t+1)=2t^2 -3t-2=2[...