函数f(x)=sin(4x+3分之派）+cos(4x-6分之派）的最小正周期和递减区间

f(x)=sin(4x+π/3）+cos(4x-π/6)=sin(4x+π-π/6）+cos(4x-π/6)=sin(π+4x-π/6）+cos(4x-π/6)=-sin(4x-π/6）+cos(4x-π/6)=-√2[√2/2*sin(4x-π/6）+√2/2*cos(4x-π/6)]=-√2[sin(4x-π/6)cosπ/4+cos(4x-π/...