(2x-1)的平方=4x^2-4x+1=ax的平方+bx+c
所以a=4,b=-4,c=1
a+c=5
4a+b+4c=16
已知:(2x-1)的平方=ax的平方+bx=c.求:a+c; 4a+b+4c的值
已知:(2x-1)的平方=ax的平方+bx=c.求:a+c; 4a+b+4c的值
数学人气:661 ℃时间:2019-11-14 15:02:44
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