所以f(x)在π/6+kπ
2、x属于[-5π/12,π/3]
2x+π/6属于[-2π/3,5π/6]
sin(2x+π/6)属于[-√3/2,1]
f(x)属于[-√3-1,1]
希望对你有帮助~那单调递增区间怎么算？-π/2+2kπ<2x+π/6<π/2+2kπ，k属于Z 2π/3+kπ
已知函数f(x)=2sin(2x+π/6)-1(x∈R) 1.求函数的单调递减增区间 2.若x属于[-5π/12,π/3],函数的取值范围
已知函数f(x)=2sin(2x+π/6)-1(x∈R) 1.求函数的单调递减增区间 2.若x属于[-5π/12,π/3],函数的取值范围
数学人气：144 ℃时间：2019-08-21 04:22:32
优质解答
1、π/2+2kπ<2x+π/6<3π/2+2kπ,k属于Z
所以f(x)在π/6+kπ
2、x属于[-5π/12,π/3]
2x+π/6属于[-2π/3,5π/6]
sin(2x+π/6)属于[-√3/2,1]
f(x)属于[-√3-1,1]
希望对你有帮助~那单调递增区间怎么算？-π/2+2kπ<2x+π/6<π/2+2kπ，k属于Z 2π/3+kπ
所以f(x)在π/6+kπ
2、x属于[-5π/12,π/3]
2x+π/6属于[-2π/3,5π/6]
sin(2x+π/6)属于[-√3/2,1]
f(x)属于[-√3-1,1]
希望对你有帮助~那单调递增区间怎么算？-π/2+2kπ<2x+π/6<π/2+2kπ，k属于Z 2π/3+kπ
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