[(a-b)^2+3a-3b]/(a-b+3)
=[(a-b)^2+3(a-b)]/(a-b+3)
=[(a-b)*(a-b+3)]/(a-b+3)
=a-b
计算:[(a-b)的平方+3a-3b]除以(a-b+3)
计算:[(a-b)的平方+3a-3b]除以(a-b+3)
数学人气:977 ℃时间:2020-01-28 01:45:34
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