DD1⊥平面平面A1B1C1D1
所以B1D1为 BD1在平面A1B1C1D1内的射影,所以∠BD1B1为线面角
边长为1的正方体
tan∠BD1B1=BB1/B1D1=1/√2=√2/2
在边长为1的正方体ABCD-A1B1C1D1中,求 BD1与平面A1B1C1D1所成角的正切值?
在边长为1的正方体ABCD-A1B1C1D1中,求 BD1与平面A1B1C1D1所成角的正切值?
数学人气：250 ℃时间：2019-09-22 05:55:39
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