设f(x)=sinπ/3x,求f(1)+f(2)+……+f(2011)

f(1)=sin(π/3)=3^0.5/2f(2)=sin(2π/3)=3^0.5/2f(3)=sin(3π/3)=0f(4)=sin(4π/3)=-3^0.5/2f(5)=sin(5π/3)=-3^0.5/2f(6)=sin(6π/3)=sin(2π)=sin(0)=0f(7)=sin(7π/3)=sin(2π+π/3)=sin(π/3)……f(1)+f(2)+f(3)...