y=cosα(sinα+cosα)=1/2sin2α+1/2cos2α+1/2=1/2根号2(sin2α+π/4)+1/2
所以最小正周期为π
函数y=cosα(sinα+cosα)的最小正周期为
函数y=cosα(sinα+cosα)的最小正周期为
数学人气:623 ℃时间:2019-10-19 05:30:33
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