a b互为倒数
得ab=1
c,d互为相反数
得c+d=0
k的绝对值是最小的正整数
得k=±1
-ab+3b=3d得3b-1=3d
怎么会得出2的?
已知a b互为倒数,c,d互为相反数,k的绝对值是最小的正整数
已知a b互为倒数,c,d互为相反数,k的绝对值是最小的正整数
(1)求k的值
1
(2)求(—ab+3b=3d)的值
2
1
(2)求(—ab+3c=3d)的值
2
(1)求k的值
1
(2)求(—ab+3b=3d)的值
2
1
(2)求(—ab+3c=3d)的值
2
其他人气:296 ℃时间:2019-08-20 00:33:23
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