若函数f(x)与g(x)分别是定义域为｛x|x≠±1｝的奇函数与偶函数且f(x)+g(x)=1/x-1,则f(x)等于多少?g(x)等

由奇,偶函数,得f(-x)=-f(x),g(-x)=g(x)f(x)+g(x)=1/x-1,f(-x)+g(-x)=-f(x)+g(x)=1/-x-1两式相加,得2g(x)=2/(x^2-1) => g(x)=1/(x^2-1)两式相减,得2f(x)=2x/(x^2-1) => f(x)=x/(x^2-1)