∵x2+2xy-1=0
∴(x+y)2=1+y2≥1
则x+y≥1或x+y≤-1
故x+y的取值范围是(-∞,-1]∪[1,+∞)
故答案为:(-∞,-1]∪[1,+∞)
设实数x,y满足x2+2xy-1=0,则x+y的取值范围是_.
设实数x,y满足x2+2xy-1=0,则x+y的取值范围是______.
数学人气:725 ℃时间:2020-05-10 11:20:24
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