若实数X满足条件(X^2+4X-5)^2+|X^2-X-30|等于0 求√(X+1)^2-√(X-1)^2

平方项与绝对值项均恒非负,两非负项之和=0,两非负项均=0x²+4x-5=0(x+5)(x-1)=0x=-5或x=1x²-x-30=0(x-6)(x+5)=0x=6或x=-5要两项同时为0,则只有x=-5√(x+1)²-√(x-1)²=|x+1|-|x-1|=|-5+1|-|-5-1|=...