[x(x²y²-xy)-y(x²-x³y)]÷3x²y
=[x²y(xy-1)-x²y(1-xy)]÷3x²y
=x²y[(xy-1)-(1-xy)]÷3x²y
=x²y[2(xy-1)]÷3x²y
=2(xy-1)/3
因式分解:[x(x²y²-xy)-y(x²-x³y)]÷3x²y
因式分解:[x(x²y²-xy)-y(x²-x³y)]÷3x²y
急 十万火急
13:40之前有奖励!
急 十万火急
13:40之前有奖励!
数学人气:830 ℃时间:2019-08-15 20:32:10
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