∵直线AB CD相交于O,角BOD=60度
∴∠AOC=60°
∵∠BOE=90°
∴∠AOE=90°
∴∠COE=∠AOC+∠AOE=60°+90°=150°
直线AB CD相交于O,E是角AOD内一点,角BOE=90度,角BOD=60度,求角COE
直线AB CD相交于O,E是角AOD内一点,角BOE=90度,角BOD=60度,求角COE
数学人气:126 ℃时间:2020-02-05 05:59:30
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