△ABC中,B=60度,cosA=4/5,b=根号3

1、由题意得,sinA=3/5∵A+B=π-C∴sinC=sin(π-C)=sin(A+B)=sinAcosB+cosAsinB=3/5*1/2+4/5*√3/2=(3+4√3)/102、根据正弦定理可得,a/sinA=b/sinB∴a=6/5S=(1/2)absinC=1/2*6/5*√3*[(3+4√3)/10]=√3+(3/10)...