求过点M(3,1)且被点M平分的双曲线4分之x平方减y平方等于1的弦所在直线方程

直线经过点M(3,1),则设所求的直线方程为:y+1=k(x-3),即y=kx-3k-1解下方程组:y=kx-3k-1.(1)x^2/4-y^2=1.(2)即可得弦与双曲线的交点坐标:x^2/4-(kx-3k-1)^2=1(0.25-k^2)x^2+2k(3k+1)x-(3k+1)^2-1=0x1+x2=-2k(3k+1)/(0....