积分上限2,积分下限1,求√x*lnx的定积分,

解法如下：∫(1→2)√x*lnxdx=(2/3)∫(1→2)lnxd x^(3/2) ←使用分部积分法=(2/3)x^(3/2)lnx(1→2)-(2/3)∫(1→2)x^(3/2)d lnx=(4√2*ln2)/3-(2/3)∫(1→2)x^(1/2)dx=(4√2*ln2)/3-(4/9)(2√2-1)以上答案仅供参考,...