sinα+cosα=1/5
两边同时平方,得:
1+2*sinαcosα=1/25
sinαcosα=-12/25
sin^3α+cos^3α
=(sinα+cosα)[(sinα)^2+(cosα)^2-sinαcosα]
=1/5* (1+12/25)
=37/125
sinα+cosα=1/5 求sin三次方α+cos三次方α
sinα+cosα=1/5 求sin三次方α+cos三次方α
数学人气:233 ℃时间:2020-01-28 16:12:59
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