已知x=√2+√5y=√5-√2求x²+xy=y²和(x+y)²-(x-y)²的值
已知x=√2+√5y=√5-√2求x²+xy=y²和(x+y)²-(x-y)²的值
是x²+xy+y²
是x²+xy+y²
数学人气:466 ℃时间:2019-08-20 11:57:49
优质解答
x²+xy+y²=(√2+√5)²+(√2+√5)(√5-√2)+(√5-√2)²=(√2+√5)²+2(√2+√5)(√5-√2)+(√5-√2)²-(√2+√5)(√5-√2)=[(√2+√5)+(√5-√2)]²-(√5+√2)(√5-√2)=(2√5)²...
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