AE=DE
BF=CF
AE/BF=DE/CF
所以角相等
如图已知四边形ABCD中AB=DC,E,F分别为AD,BC中点,BA,FE的延长线交与M,CD,EF的延长线交与N求角BMF=角CNF.
如图已知四边形ABCD中AB=DC,E,F分别为AD,BC中点,BA,FE的延长线交与M,CD,EF的延长线交与N求角BMF=角CNF.
数学人气：586 ℃时间：2019-08-21 22:51:27
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