a²+4ab+b²=(a²+2ab)+(b²+2ab)=-10+16=6
a²+2ab-(b²+2ab)=a²+2ab-b²-2ab=a²-b²=-10-16=-26
a²-b²=-26
求解答a的平方+2ab=-10,b的平方+2ab=16,则a的平方+4ab+b的平方= ;a方-b方=
求解答a的平方+2ab=-10,b的平方+2ab=16,则a的平方+4ab+b的平方= ;a方-b方=
数学人气:737 ℃时间:2019-10-14 02:25:07
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