x²-x-1=0
x²-x=1
-x³+2x²+2010
=-x(x²-x)+x²+2010
=-x+x²+2010
=1+2010
=2011
已知x²-x-1=0,试求-x³+2x²+2010的值
已知x²-x-1=0,试求-x³+2x²+2010的值
数学人气：749 ℃时间：2020-04-21 09:47:54
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