已知{(x²+y²)-(x-y)²+2y(x-y)}÷4y=1,求4x²-y²分之4x -- 2x+y分之1 的值!
已知{(x²+y²)-(x-y)²+2y(x-y)}÷4y=1,求4x²-y²分之4x -- 2x+y分之1 的值!
数学人气：940 ℃时间：2019-10-17 03:22:58
优质解答
{(x²+y²)-(x-y)²+2y(x-y)}÷4y=1{x²+y²-(x²-2xy+y²)+2xy-2y²}÷4y=1{x²+y²-x²+2xy-y²+2xy-2y²}÷4y=1{4xy-2y²}÷4y=12y{2x-y}÷4y=1{2x-y}...
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