解由1/X+2/Y
=(1/X+2/Y)×1
=(1/X+2/Y)×(x+2Y)/3
=1/3(1/X+2/Y)×(x+2Y)
=1/3(1+4+2x/Y+2Y/X)
=5/3+1/3(2X/Y+2Y/X)
≥5/3+1/3×2√2X/Y×2Y/X
=5/3+4/3
=3
故
1/X+2/Y的最小值为3.
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