求不定积分:∫((1-x²)∧(1/2))/x² dx 文字描述:根号下一减x的平方除以x方.分子和

令x = sint,dx = cost dt
∫ √(1 - x²)/x² dx
= ∫ (cosx/sin²t)(cost dt)
= ∫ cot²t dt
= ∫ (csc²t - 1) dt
= - cott - t + C
= - √(1 - x²)/x - arcsinx + C