已知在三角形ABC中,A=45°,a=2,c=√6,解此三角形

a/sinA = c/sinC => sinC = c * sinA /a = =√6 * √2 / 4 = =√3 /2
C = 60°或 120°具体过程。正弦定理a/sinA = c/sinC = b/SinB ……A=45°， C=60°， B=75°或 A=45°， C=120°， B=15°b也求一下吧。A=45°， C=60°， B=75° , sinB = sin(45°+30°) = (1+√3)/(2√2)a/sinA = b/SinB=> b = a sinB / sinA = (1+√3)A=45°， C=120°， B=15°,sinB = sin(45°- 30°) = (√3-1)/(2√2)a/sinA = b/SinB=> b = a sinB / sinA = ( -1+√3)