sin2x+cos2x=(根号下2)sin(2x+π/4)
sin2x+cos2x=(根号下2)[根号下2/2sian2x+根号下2/2cos2x]
=(根号下2)[cosπ/4sin2x+sinπ/4cos2x]
=(根号下2)sin(2x+π/4)
为什么sin2x+cos2x=2sin(2x+π/4)
为什么sin2x+cos2x=2sin(2x+π/4)
数学人气：801 ℃时间：2019-11-15 06:59:23
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