b=1/a ,代入根式,可以化简得
原式=1/(a^2)+a^2=a^2+b^2=(a+b)^-2ab=9-2=7
已知实数a+b=-3,ab=1,求(b√b/a)+(a√a/b)的值
已知实数a+b=-3,ab=1,求(b√b/a)+(a√a/b)的值
数学人气:547 ℃时间:2020-03-30 23:07:07
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