已知f(x)为奇函数,g(x)=f(x-2)为偶函数,且f(3)=5,则f(2007)= ,f(2008)=

g(x)=f(x-2) = g(-x) //g(x)偶函数g(-x)=f(-x-2) = -f(x+2) //f(x)奇函数所以 f(x-2) = -f(x+2) 式(1)f(x+2) = f(x+4 -2) = -f(x+4 +2) = -f(x+6)f(x-2) = f(x+6)f(x) = f(x+8) //f(x) 以8为周期f(2008) = f(0) = 0 ...