f(x\x+1)-2f(1\1+x)=(x+2)\(x-1)求f(x)

已知f[x/(x+1)]-2f(1/(x+1)]=(x+2)/x-1),求f(x)f[x/(x+1)]-2f(1/(x+1)]=(x+2)/x-1),f(1-1/(x+1))-2f(1/(x+1))=(x+1+1)/(x+1-2)=[1+1/(x+1)]/(1-2/(x+1))用x代替上式中的1/(1+x)：即：f(1-x)-2f(x)=(1+x)/(1-2x).(1)...