若（｜x+1｜+｜x+2｜）（｜y-2｜+｜y+1｜）（｜z-3｜+｜z+1｜）＝36,则x+2y+3z的最大值是

若(|x+1|+|x-2|)(|y-2|+|y+1|)(|z-3|+|z+1|)=36,则x+2y+3z的最大值是______,最小值是_____.15；-6∵|X+1|+|X-2|≥3,|Y-2|+|Y+1|≥3,|Z-3|+|Z+1|≥4(|X+1|+|X-2|)(|Y-2|+|Y+1|)(|Z-3|+|Z+1|)≥3*3*4=36,∴|X+1|+|X-2|...