d/dx定积分(0~x^2) (1+t^2)^(1/2)dt d/dx定积分(0~x^2)(x^1/2)cost^2dt
d/dx定积分(0~x^2) (1+t^2)^(1/2)dt d/dx定积分(0~x^2)(x^1/2)cost^2dt
请帮我解答下 感激不尽
请帮我解答下 感激不尽
其他人气:897 ℃时间:2020-02-05 07:06:52
优质解答
1、=2x(1+x^4)^(1/2)2、=d/dx(x^1/2)*∫ (0~x^2)cost^2dt=(1/2)x^(-1/2)*∫ (0~x^2)cost^2dt+(x^(1/2))*cos(x^4) *2x=(1/2)x^(-1/2)*∫ (0~x^2)cost^2dt+2(x^(3/2))*cos(x^4)
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