已知直线y=x+b与抛物线x^2=2y交于A,B两点,且OA垂直于OB（O为坐标原点）,求b的取值范围请写清楚过程谢谢

y = x + b = x²/2x² - 2x -2b = 0x1 = 1+ √(1+2b),y1 = 1+b + √(1+2b),OA的斜率为k1 = [1+b + √(1+2b)]/[1+ √(1+2b)]x2 = 1- √(1+2b),y2 = 1+b -√(1+2b),OB的斜率为k2 = [1+b - √(1+2b)]/[1- √(1+...