延长AD到E,使AD=DE,连接CE,BE,
∵AD=DE,BD=CD,
∴四边形ABEC是平行四边形,
∴AB∥CE,AB=CE,
∵AB=2AC,∠CAE=90°,
∴在直角△EAC中,CE=2AC,
∴∠AEC=30°,
∴∠BAD=∠AEC=30°,
∴∠BAC=30°+90°=120°.
故答案为:120°.
如图,△ABC中,AB=2AC,AD平分BC且AD⊥AC,则∠BAC=_.
如图,△ABC中,AB=2AC,AD平分BC且AD⊥AC,则∠BAC=______.
数学人气:495 ℃时间:2019-08-19 23:15:25
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